The sides AB, BC &Best answer Taking out a, b, c common from I, II, and III row respectively, we get (the determinant of a triangular matrix is the product of its diagonal elements) =ab bc ca abcAnd AB BC CA = 12 cm Write true or false and give reason for your answer
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If ab bc ca 4 and abc=2-Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreHow do you factor #(abc)(abbcca)abc#?
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计算(abc)(a平方b平方c平方 ab bc ca)： 原式=a³ab²ac²a²babca²ca²bb³bc²ab²b²cabca²cb²cc³abcbc²ac²=a³b³c³3abc abc 3abc=(abc)(abc ab bc ca)这个公式怎么得到的?： ﹙ a²﹢b²c²abbcca﹚﹙abc﹚ =a^3ab^2ac^2a^2babca^2ca^2bb^3bc^2ab^2b^2cabca^2cbPosted by Amit Kumar Sinha 2 days, 1 hour ago CBSE >In a triangle ABC, AB = BC = CA The ratio of the radius of the circumcircle to that of the incircle is A) 2 1 B) 3 1 C) 3 2 D) None of these Correct Answer A) 2
If (abc)(abbcca)=abc then prove that (abc)^3=a^3b^3c^3Ab bc ca = 2 abc = 2 Formula used (a b c) 2 = a 2 b 2 c 2 2(ab bc ca) a 3 b 3 c 3 3abc = (a b c)a 2 b 2 c 2 (ab bc ca) Calculation (a b c) = 2 On squaring both sides, we get ⇒ a 2 b 2 c 2 2(ab bc ca) = 4 ⇒ a 2 b 2 c 2 2(2) = 4 ⇒ a 2 bA 3 b 3 c 3 3abc = (a b c) (a 2 b 2 c 2 ab bc ca) Where a = 2a, b = 3b and c = 5c Now apply values of a, b and c on the LHS of identity ie a 3 b 3 c 3 3abc = (a b c) (a 2 b 2 c 2 ab bc ca) and we get = (2a 3b 5c) { (2a) 2 (3b) 2 (5c) 2 – (2a) (3b) – (3b) (5c) – (5c) (2a) }
SolutionShow Solution As a, b, c, are in continued proportion Let `a/b = b/c` = k LHS = abc (a b c) 3 = ck 2 ckc ck 2 ck c 3 = c 3 k 3 c (k 2 k 1) 3 = c 3 k 3 c 3 (k 2 k 1) 3 = c6k 3 (k 2 k 1) 3 RHS = (ab bc ca) 3In a triangle ABC, AB BC = 12 cm, BC CA =14 cm and CA AB = 18 cm Find the radius of the circle (in cm) which has the same perimeter as the triangleThe equation of the sides AB,BC,CA of a triangle ABC are 2xy=0, xpy=q , xy=3 respectively The point P is (2,3) Find 1) If P is the centroid, then find pq 2) If P is the orthocentre, the find pq 3) If P is the circumcentre, then find pq Maths Straight Lines
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Solution for abbcca=abc equation Simplifying ab bc ca = abc Reorder the terms ab ac bc = abc Solving ab ac bc = abc Solving for variable 'a' Move all terms containing a to the left, all other terms to the right Add '1abc' to each side of the equation ab ac 1abc bc = abc 1abc Reorder the terms ab 1abc ac bc = abc 1abc Combine like terms abc 1abc = 0 ab 1abc ac bc = 0 Add '1bc' to each side of the equation abLet S = a b c Then LHS = (s c)(s a)(s b) = s^3 (S^2(a b c) (s)(AB BC ca) (abc) = (s)(ab BC ca)(abc) QED∆ABC is such that AB = 3 cm, BC = 2 cm and CA = 25 cm If ∆DEF ~ ∆ABC and EF = 4 cm, then perimeter of ∆DEF is (a) 75 cm (b) 15 cm (c) 225 cm (d) 30 cm Solution (b) ∆DEF ~ ∆ABC AB = 3 cm, BC = 2 cm, CA = 25 cm, EF = 4 cm ∆s are similar Question 41 In ∆ABC, a line XY parallel to BC cuts AB at X and AC at Y If BY bisects
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In ∆ABC, The length of sides AB, BC and AC are 6√2 cm, 9 cm and 12 cm respectively In ∆PQR, The length of sides PR, QR, PQ are 2√2 cm, 3 cm and 4 cm respectively Also given that ∠A and ∠B are 30°Respectively Find the value of ∠Q OptionsClick here👆to get an answer to your question ️ In ABC , angle A is 1^∘ , BC CA = , and AB BC = 21 Find the length of the side BC
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3 views asked 7 hours ago in Mathematics by MukeshKumar (212k points) If the sides AB, BC and CA of a triangle ABC have 3, 5 and 6 interior points respectively, then the total number of triangles that can be constructed using these points as vertices, is equal toIf P, Q and R are the midpoints of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic asked in Class IX Maths by aman28 ( 872 points)Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
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Ex 64, 5 D, E and F are respectively the midpoints of sides AB, BC and CA of ΔABC Find the ratio of the areas of ΔDEF and ΔABC Given Δ ABC &5 interior points respectively on them Find the number of triangles that can be constructed usingMaths NCERT Solutions Class 9 Chapter 9 Exercise 93 Question 5 Summary D, E, and F are respectively the midpoints of the sides BC, CA, and AB of triangle ABC, then BDEF is a parallelogram, Area of (DEF) = 1/4 Area of (ABC), and Area of (BDEF) = 1/2 Area of (ABC)
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The sides AB, BC, CA of a triangle ABC have 3, 4 and 5 interior points respectively on them Find the number of triangles that can be constructed using these points as vertices Medium Open in App Solution Verified by Toppr First note in all 3 4Given that ABC is an isosceles triangle where AB = AC Since D, E, F are the midpoint of AB, BC, CA therefore 2DE = AC and 2EF = AB this means DE = EF Therefore DEF is an isosceles triangle a DE = EF Hence provedSOLUTION Using the property of triangle, sum of any two sides has to be greater than the third side and difference of the two sides has to be lesser than the third side Sum of the two sides other than AC = AB BC = 21 CM Difference of the two sides other than AC = AB – BC
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Solved Example on Simplification of (a b c)(a\(^{2}\) b\(^{2}\) c\(^{2}\) – ab – bc – ca) 1 Simplify (x 2y 3z)(x\(^{2}\) 4y\(^{2}\) 9z\(^{2Your trusted source for breaking news, analysis, exclusive interviews, headlines, and videos at ABCNewscomAlgebra 1 Answer Jack H #(ab)(bc)(ca)# Explanation Answer link Related questions How do I determine the molecular shape of a molecule?
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One way to arrive at the simplified expression is $ABA(\neg C)BC=AB(C(\neg C))A(\neg C)(B(\neg B))BC(A(\neg A))=ABCAB(\neg C)AB(\neg C)A(\neg B)(\neg C)ABC(\neg A)BC=ABCAB(\neg C)A(\neg B)(\neg C)(\neg A)BC=BC(A(\neg A))A(\neg C)(B(\neg B))=BCA(\neg C)$$\endgroup$– laissez_faireSep 6 '16 at 1915Three sides AB BC and CA of a triangle ABC are 5x−3y2= Three sides AB, BC and CA of a triangle ABC are 5x−3y2 =0, x−3y−2 =0 and xy−6 =0 respectively Find the equation of the altitude through the vertex A Please scroll down to see the correct answer and solution guide1 Phân tích thành nhân tử (a b c)(ab bc ca)− abc ( a b c) ( a b b c c a) − a b c Theo dõi Vi phạm YOMEDIA Toán 8 Bài 6 Trắc nghiệm Toán 8 Bài 6 Giải bài tập Toán 8 Bài 6
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9OMO 14 Let ABC be a triangle with incenter I and AB = 1400, AC = 1800, BC = 14 The circle centered at I passing through A intersects line BC at two points X and Y Compute the length XY 10India RMO 14 Let ABC be an isosceles triangle with AB = AC and let denote its circumcircle A point D is on arc AB of not containing CEx 102, 18 (MCQ) In triangle ABC which is not true AB BC CA = 0 Chapter 10 Class 12 Vector Algebra (Term 2) Serial order wise Ex 102Integer solutions to abc = 2 (abbcca) WolframAlpha Rocket science?
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A triangle ABC can be constructed in which ∠B = 60°, ∠C = 45°Equations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations (abc)(abbcca)abc so that you understand betterThere is likely 1/b1/c) ≥ (abc) 2 Now, the LHS = (1/b1/c) = (sqrt () 2 sqrt (1/b) 2 sqrt (1/c) 2) Then, by CauchyShwartz
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If a b c 6 and ab bc ca 11 find the value of a3 b3 c3 3abc Mathematics TopperLearningcom 3vrgnejoo OneonOne Online Live Interactive DoubtAb bc ca does not exceed aa bb cc Several proofs The inequality below, though simple, is useful and often comes up in proofs of more involved inequalities= a 3 b 3 c 3 a 2 b a 2 b ac 2 ac 2 ab 2 ab 2 bc 2 bc 2 a 2 c a 2 c b 2 c b 2 c abc abc abc Above highlighted like terms will be subtracted and we get = a 3 b 3 c 3 abc abc abc Join like terms ie (abc) and we get = a 3 b 3 c 3 3abc Hence, in this way we obtain the identity ie a 3 b 3 c
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